What is the smallest number greater than 1 that leaves a remainder of 1 when divided by 2, 3, 4, 5 or 6?

Correct answer: C. 61

The LCM of 2, 3, 4, 5 and 6 is 60, so the number is 60 + 1 = 61. 121 also works but is larger, while 31 and 59 fail (31 ÷ 4 leaves 3, and 59 ÷ 3 leaves 2).

hard

Answer and explanation

The correct answer is C. 61

The LCM of 2, 3, 4, 5 and 6 is 60, so the number is 60 + 1 = 61. 121 also works but is larger, while 31 and 59 fail (31 ÷ 4 leaves 3, and 59 ÷ 3 leaves 2).

Topic: Age and Number Problems MCQs · Subject: Numerical Ability